How to solve b - b < 8 - 4b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve b - b < 8 - 4b | Equatix

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$$b-b<8-4b$$

$b<2$

Combine $b$ and $-b$ to get $0$.

$$0<8-4b$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$8-4b>0$$

Subtract $8$ from both sides. Anything subtracted from zero gives its negation.

$$-4b>-8$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$b<\frac{-8}{-4}$$

Divide $-8$ by $-4$ to get $2$.

$$b<2$$