Solve B(x)=(-6x-1)(x+2)-(7x-2)(-x-4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$B(x)=(-6x-1)(x+2)-(7x-2)(-x-4)$$

Evaluate

$x^{2}+13x-10$

Solution Steps

Apply the distributive property by multiplying each term of $-6x-1$ by each term of $x+2$.

$$-6x^{2}-12x-x-2-\left(7x-2\right)\left(-x-4\right)$$

Combine $-12x$ and $-x$ to get $-13x$.

$$-6x^{2}-13x-2-\left(7x-2\right)\left(-x-4\right)$$

Apply the distributive property by multiplying each term of $7x-2$ by each term of $-x-4$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-28x-2\left(-x\right)+8\right)$$

Multiply $-2$ and $-1$ to get $2$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-28x+2x+8\right)$$

Combine $-28x$ and $2x$ to get $-26x$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-26x+8\right)$$

To find the opposite of $7x\left(-x\right)-26x+8$, find the opposite of each term.

$$-6x^{2}-13x-2-7x\left(-x\right)-\left(-26x\right)-8$$

Multiply $-7$ and $-1$ to get $7$.

$$-6x^{2}-13x-2+7xx-\left(-26x\right)-8$$

Multiply $x$ and $x$ to get $x^{2}$.

$$-6x^{2}-13x-2+7x^{2}-\left(-26x\right)-8$$

Combine $-6x^{2}$ and $7x^{2}$ to get $x^{2}$.

$$x^{2}-13x-2-\left(-26x\right)-8$$

The opposite of $-26x$ is $26x$.

$$x^{2}-13x-2+26x-8$$

Combine $-13x$ and $26x$ to get $13x$.

$$x^{2}+13x-2-8$$

Subtract $8$ from $-2$ to get $-10$.

$$x^{2}+13x-10$$

Expand

$x^{2}+13x-10$

Solution Steps

Apply the distributive property by multiplying each term of $-6x-1$ by each term of $x+2$.

$$-6x^{2}-12x-x-2-\left(7x-2\right)\left(-x-4\right)$$

Combine $-12x$ and $-x$ to get $-13x$.

$$-6x^{2}-13x-2-\left(7x-2\right)\left(-x-4\right)$$

Apply the distributive property by multiplying each term of $7x-2$ by each term of $-x-4$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-28x-2\left(-x\right)+8\right)$$

Multiply $-2$ and $-1$ to get $2$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-28x+2x+8\right)$$

Combine $-28x$ and $2x$ to get $-26x$.

$$-6x^{2}-13x-2-\left(7x\left(-x\right)-26x+8\right)$$

To find the opposite of $7x\left(-x\right)-26x+8$, find the opposite of each term.

$$-6x^{2}-13x-2-7x\left(-x\right)-\left(-26x\right)-8$$

Multiply $-7$ and $-1$ to get $7$.

$$-6x^{2}-13x-2+7xx-\left(-26x\right)-8$$

Multiply $x$ and $x$ to get $x^{2}$.

$$-6x^{2}-13x-2+7x^{2}-\left(-26x\right)-8$$

Combine $-6x^{2}$ and $7x^{2}$ to get $x^{2}$.

$$x^{2}-13x-2-\left(-26x\right)-8$$

The opposite of $-26x$ is $26x$.

$$x^{2}-13x-2+26x-8$$

Combine $-13x$ and $26x$ to get $13x$.

$$x^{2}+13x-2-8$$

Subtract $8$ from $-2$ to get $-10$.

$$x^{2}+13x-10$$