Question

$$\bullet1\frac{3x}{7}-\frac{x+1}{14}=7$$

Answer

$$b=(x-107)/(91*e*u*l^2*t*x)$$

Solution


Take out the constants.
\[(13\times 7)bulltxe-x+114=7\]
Simplify  \(13\times 7\)  to  \(91\).
\[91bulltxe-x+114=7\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[91bu{l}^{2}txe-x+114=7\]
Regroup terms.
\[91ebu{l}^{2}tx-x+114=7\]
Add \(x\) to both sides.
\[91ebu{l}^{2}tx+114=7+x\]
Subtract \(114\) from both sides.
\[91ebu{l}^{2}tx=7+x-114\]
Simplify  \(7+x-114\)  to  \(x-107\).
\[91ebu{l}^{2}tx=x-107\]
Divide both sides by \(91\).
\[ebu{l}^{2}tx=\frac{x-107}{91}\]
Divide both sides by \(e\).
\[bu{l}^{2}tx=\frac{\frac{x-107}{91}}{e}\]
Simplify  \(\frac{\frac{x-107}{91}}{e}\)  to  \(\frac{x-107}{91e}\).
\[bu{l}^{2}tx=\frac{x-107}{91e}\]
Divide both sides by \(u\).
\[b{l}^{2}tx=\frac{\frac{x-107}{91e}}{u}\]
Simplify  \(\frac{\frac{x-107}{91e}}{u}\)  to  \(\frac{x-107}{91eu}\).
\[b{l}^{2}tx=\frac{x-107}{91eu}\]
Divide both sides by \({l}^{2}\).
\[btx=\frac{\frac{x-107}{91eu}}{{l}^{2}}\]
Simplify  \(\frac{\frac{x-107}{91eu}}{{l}^{2}}\)  to  \(\frac{x-107}{91eu{l}^{2}}\).
\[btx=\frac{x-107}{91eu{l}^{2}}\]
Divide both sides by \(t\).
\[bx=\frac{\frac{x-107}{91eu{l}^{2}}}{t}\]
Simplify  \(\frac{\frac{x-107}{91eu{l}^{2}}}{t}\)  to  \(\frac{x-107}{91eu{l}^{2}t}\).
\[bx=\frac{x-107}{91eu{l}^{2}t}\]
Divide both sides by \(x\).
\[b=\frac{\frac{x-107}{91eu{l}^{2}t}}{x}\]
Simplify  \(\frac{\frac{x-107}{91eu{l}^{2}t}}{x}\)  to  \(\frac{x-107}{91eu{l}^{2}tx}\).
\[b=\frac{x-107}{91eu{l}^{2}tx}\]