How to solve bx - 2x = 8 + 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve bx - 2x = 8 + 2 | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$bx-2x=8+2$$

Solve for b

$b=2+\frac{10}{x}$
$x\neq 0$

Steps for Solving Linear Equation

Add $8$ and $2$ to get $10$.

$$bx-2x=10$$

Add $2x$ to both sides.

$$bx=10+2x$$

The equation is in standard form.

$$xb=2x+10$$

Divide both sides by $x$.

$$\frac{xb}{x}=\frac{2x+10}{x}$$

Dividing by $x$ undoes the multiplication by $x$.

$$b=\frac{2x+10}{x}$$

Divide $10+2x$ by $x$.

$$b=2+\frac{10}{x}$$

Show Solution

Solve for x

$x=\frac{10}{b-2}$
$b\neq 2$

Steps for Solving Linear Equation

Add $8$ and $2$ to get $10$.

$$bx-2x=10$$

Combine all terms containing $x$.

$$\left(b-2\right)x=10$$

Divide both sides by $b-2$.

$$\frac{\left(b-2\right)x}{b-2}=\frac{10}{b-2}$$

Dividing by $b-2$ undoes the multiplication by $b-2$.

$$x=\frac{10}{b-2}$$

Show Solution

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Example

Question

Solve for b

Steps for Solving Linear Equation

Solve for x

Steps for Solving Linear Equation