Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$bx+ay=(a+ { b }^{ 2 } ) \frac{ { a }^{ 2 } + { b }^{ 2 } -1 }{ }$$

Answer

$$x=((a+b^2)*(a^2+b^2-1)-a*y)/b$$

Solution


Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[bx+ay=(a+{b}^{2})({a}^{2}+{b}^{2}-1)\]
Subtract \(ay\) from both sides.
\[bx=(a+{b}^{2})({a}^{2}+{b}^{2}-1)-ay\]
Divide both sides by \(b\).
\[x=\frac{(a+{b}^{2})({a}^{2}+{b}^{2}-1)-ay}{b}\]
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