Solve C = (27 * 9) - |(25 * 12) / 15| + 5 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$C=(27\times9)-|(25\times12)\div15|+5.$$

Solve for C

$C=228$

Steps for Solving Linear Equation

Multiply $27$ and $9$ to get $243$.

$$C=243-|\frac{25\times 12}{15}|+5$$

Multiply $25$ and $12$ to get $300$.

$$C=243-|\frac{300}{15}|+5$$

Divide $300$ by $15$ to get $20$.

$$C=243-|20|+5$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $20$ is $20$.

$$C=243-20+5$$

Subtract $20$ from $243$ to get $223$.

$$C=223+5$$

Add $223$ and $5$ to get $228$.

$$C=228$$

Assign C

$C≔228$