Solve C = (sqrt(5) + 1) ^ 2 - 2sqrt(5) | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$C=(\sqrt{5}+1)^{2}-2\sqrt{5}$$

Solve for C

$C=6$

Steps for Solving Linear Equation

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(\sqrt{5}+1\right)^{2}$.

$$C=\left(\sqrt{5}\right)^{2}+2\sqrt{5}+1-2\sqrt{5}$$

The square of $\sqrt{5}$ is $5$.

$$C=5+2\sqrt{5}+1-2\sqrt{5}$$

Add $5$ and $1$ to get $6$.

$$C=6+2\sqrt{5}-2\sqrt{5}$$

Combine $2\sqrt{5}$ and $-2\sqrt{5}$ to get $0$.

$$C=6$$

Assign C

$C≔6$