$$C(6+8\div(4+2)$$
$\frac{22C}{3}$
$$C\left(6+\frac{8}{6}\right)$$
$$C\left(6+\frac{4}{3}\right)$$
$$C\left(\frac{18}{3}+\frac{4}{3}\right)$$
$$C\times \frac{18+4}{3}$$
$$C\times \frac{22}{3}$$
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