Question

$$C3a+2b=20$$

Solve for C_3 (complex solution)

$\left\{\begin{matrix}C_{3}=-\frac{2\left(b-10\right)}{a}\text{, }&a\neq 0\\C_{3}\in \mathrm{C}\text{, }&b=10\text{ and }a=0\end{matrix}\right.$

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Solve for a (complex solution)

$\left\{\begin{matrix}a=-\frac{2\left(b-10\right)}{C_{3}}\text{, }&C_{3}\neq 0\\a\in \mathrm{C}\text{, }&b=10\text{ and }C_{3}=0\end{matrix}\right.$

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Solve for C_3

$\left\{\begin{matrix}C_{3}=-\frac{2\left(b-10\right)}{a}\text{, }&a\neq 0\\C_{3}\in \mathrm{R}\text{, }&b=10\text{ and }a=0\end{matrix}\right.$

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Solve for a

$\left\{\begin{matrix}a=-\frac{2\left(b-10\right)}{C_{3}}\text{, }&C_{3}\neq 0\\a\in \mathrm{R}\text{, }&b=10\text{ and }C_{3}=0\end{matrix}\right.$

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