How to solve c3x + 2 = 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve c3x + 2 = 5 | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$c3x+2=5$$

Solve for c_3

$c_{3}=\frac{3}{x}$
$x\neq 0$

Steps for Solving Linear Equation

Subtract $2$ from both sides.

$$c_{3}x=5-2$$

Subtract $2$ from $5$ to get $3$.

$$c_{3}x=3$$

The equation is in standard form.

$$xc_{3}=3$$

Divide both sides by $x$.

$$\frac{xc_{3}}{x}=\frac{3}{x}$$

Dividing by $x$ undoes the multiplication by $x$.

$$c_{3}=\frac{3}{x}$$

Show Solution

Solve for x

$x=\frac{3}{c_{3}}$
$c_{3}\neq 0$

Steps for Solving Linear Equation

Subtract $2$ from both sides.

$$c_{3}x=5-2$$

Subtract $2$ from $5$ to get $3$.

$$c_{3}x=3$$

Divide both sides by $c_{3}$.

$$\frac{c_{3}x}{c_{3}}=\frac{3}{c_{3}}$$

Dividing by $c_{3}$ undoes the multiplication by $c_{3}$.

$$x=\frac{3}{c_{3}}$$

Show Solution

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Example

Question

Solve for c_3

Steps for Solving Linear Equation

Solve for x

Steps for Solving Linear Equation