How to solve C93+72*6+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve C93+72*6+10 | Equatix

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Question

$$C93+72\times6+10$$

Evaluate

$C_{93}+442$

Show Solution

Differentiate w.r.t. C_93

$1$

Steps Using Derivative Rule for Sum

Multiply $72$ and $6$ to get $432$.

$$\frac{\mathrm{d}}{\mathrm{d}C_{93}}(C_{93}+432+10)$$

Add $432$ and $10$ to get $442$.

$$\frac{\mathrm{d}}{\mathrm{d}C_{93}}(C_{93}+442)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$C_{93}^{1-1}$$

Subtract $1$ from $1$.

$$C_{93}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. C_93

Steps Using Derivative Rule for Sum