$\frac{8\left(co\left(\sin(x)\right)^{3}-\left(\cos(x)\right)^{6}\right)}{\left(\sin(2x)\right)^{3}}$

$\frac{48\left(co\left(\sin(x)\right)^{5}+\left(\cos(x)\right)^{6}\right)}{\left(\sin(2x)\right)^{4}}$