Question

$$COS(26+ \frac{ x }{ 5 } )=SIN(14+ \frac{ 4x }{ 5 } )$$

Answer

x=-0

Solution


Remove parentheses.
\[COS26+\frac{x}{5}=SIN14+\frac{4x}{5}\]
Multiply both sides by \(5\).
\[5COS26+x=5SIN14+4x\]
Subtract \(5COS26\) from both sides.
\[x=5SIN14+4x-5COS26\]
Subtract \(4x\) from both sides.
\[x-4x=5SIN14-5COS26\]
Simplify  \(x-4x\)  to  \(-3x\).
\[-3x=5SIN14-5COS26\]
Divide both sides by \(-3\).
\[x=-\frac{5SIN14-5COS26}{3}\]
Factor out the common term \(5\).
\[x=-\frac{5(SIN14-COS26)}{3}\]
Rewrite \(SIN14-COS26\) in the form \({a}^{2}-{b}^{2}\), where \(a=0\) and \(b=0\).
\[x=-\frac{5({0}^{2}+{0}^{2})}{3}\]
Simplify  \({0}^{2}\)  to  \(0\).
\[x=-\frac{5(0+0)}{3}\]
Simplify  \(0+0\)  to  \(0\).
\[x=-\frac{5\times 0}{3}\]
Simplify  \(5\times 0\)  to  \(0\).
\[x=-\frac{0}{3}\]
Simplify  \(\frac{0}{3}\)  to  \(0\).
\[x=-0\]