$$\cos ^ { 2 } 45 ^ { \circ } + \tan ^ { 2 } 60 ^ { \circ } = 2$$
$\text{false}$
$$\left(\frac{\sqrt{2}}{2}\right)^{2}+\left(\tan(60)\right)^{2}=2$$
$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+\left(\tan(60)\right)^{2}=2$$
$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+\left(\sqrt{3}\right)^{2}=2$$
$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+3=2$$
$$\frac{\left(\sqrt{2}\right)^{2}}{2^{2}}+\frac{3\times 2^{2}}{2^{2}}=2$$
$$\frac{\left(\sqrt{2}\right)^{2}+3\times 2^{2}}{2^{2}}=2$$
$$\frac{2+3\times 2^{2}}{2^{2}}=2$$
$$\frac{2+3\times 4}{2^{2}}=2$$
$$\frac{2+12}{2^{2}}=2$$
$$\frac{14}{2^{2}}=2$$
$$\frac{14}{4}=2$$
$$\frac{7}{2}=2$$
$$\frac{7}{2}=\frac{4}{2}$$
$$\text{false}$$
Show Solution
Hide Solution
