Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\cos^{2}60^{\circ}+\sec^{2}60^{\circ}-4=$$

Answer

$$cos(60*deg)^2+sec(60*deg)^2-4$$

Solution


Remove parentheses.
\[\cos^{2}(60deg)+\sec^{2}(60deg)-4\]
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