Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$cualeselma \xi modivisorde2Y5$$

Answer

$$-10*e^3*IM*c*u*a^2*l^2*s^2*m^2*x*o^2*d^2*v*r*Y$$

Solution


Take out the constants.
\[(2\times 5)cuaallssmmxooddvrYee\imath \imath \imath e\]
Simplify  \(2\times 5\)  to  \(10\).
\[10cuaallssmmxooddvrYee\imath \imath \imath e\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[10cu{a}^{2}{l}^{2}{s}^{2}{m}^{2}x{o}^{2}{d}^{2}vrY{e}^{3}{\imath }^{3}\]
Isolate \({\imath }^{2}\).
\[10cu{a}^{2}{l}^{2}{s}^{2}{m}^{2}x{o}^{2}{d}^{2}vrY{e}^{3}{\imath }^{2}\imath \]
Use Square Rule: \({i}^{2}=-1\).
\[10cu{a}^{2}{l}^{2}{s}^{2}{m}^{2}x{o}^{2}{d}^{2}vrY{e}^{3}\times -1\times \imath \]
Simplify.
\[-10cu{a}^{2}{l}^{2}{s}^{2}{m}^{2}x{o}^{2}{d}^{2}vrY{e}^{3}\imath \]
Regroup terms.
\[-10{e}^{3}\imath cu{a}^{2}{l}^{2}{s}^{2}{m}^{2}x{o}^{2}{d}^{2}vrY\]
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