$$\{15\times15-(-3)\}(4-4)\div3\{5+(-3)\times(-6)\}$$
$0$
$$\frac{\left(225-\left(-3\right)\right)\left(4-4\right)}{3}\left(5-3\left(-6\right)\right)$$
$$\frac{\left(225+3\right)\left(4-4\right)}{3}\left(5-3\left(-6\right)\right)$$
$$\frac{228\left(4-4\right)}{3}\left(5-3\left(-6\right)\right)$$
$$\frac{228\times 0}{3}\left(5-3\left(-6\right)\right)$$
$$\frac{0}{3}\left(5-3\left(-6\right)\right)$$
$$0\left(5-3\left(-6\right)\right)$$
$$0\left(5+18\right)$$
$$0\times 23$$
$$0$$
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