How to solve (2)^(2)+7(2)+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2)^(2)+7(2)+10 | Equatix

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3(r+2s)=2t-4

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Question

$${ 2 }^{ 2 } +7(2)+10$$

Evaluate

$28$

Solution Steps

Calculate $2$ to the power of $2$ and get $4$.

$$4+7\times 2+10$$

Multiply $7$ and $2$ to get $14$.

$$4+14+10$$

Add $4$ and $14$ to get $18$.

$$18+10$$

Add $18$ and $10$ to get $28$.

$$28$$

Show Solution

Factor

$2^{2}\times 7$

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