$${ 2 }^{ 2x } \times { 2 }^{ 2 } \times 5= \frac{ 13 }{ 16 }$$
$x=\frac{\log_{2}\left(\frac{13}{5}\right)}{2}-3\approx -2.310744188$
$x=\frac{\pi n_{1}i}{\ln(2)}+\frac{\log_{2}\left(\frac{13}{320}\right)}{2}$
$n_{1}\in \mathrm{Z}$
