$${ 2 }^{ a } =27va { 3 }^{ b } =64$$
$2^{a}=27av\times 3^{b}\text{ and }27av\times 3^{b}=64$
$v=\frac{32}{81\times 3^{b}}$
$a=6$
$b=-\frac{\ln(v)+\ln(\frac{81}{32})}{\ln(3)}$
$a=6\text{ and }v>0$
