Question

$${ 2 }^{ -3 } +( { \left(0.01) \right) }^{ -1 } - { 27 }^{ \frac{ 2 }{ 3 } }$$

Answer

729/8

Solution


Remove parentheses.
\[{2}^{-3}+{0.01}^{-1}-{27}^{\frac{2}{3}}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{1}{{2}^{3}}+{0.01}^{-1}-{27}^{\frac{2}{3}}\]
Simplify  \({2}^{3}\)  to  \(8\).
\[\frac{1}{8}+{0.01}^{-1}-{27}^{\frac{2}{3}}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{1}{8}+\frac{1}{0.01}-{27}^{\frac{2}{3}}\]
Rewrite \(27\) as \({3}^{3}\).
\[\frac{1}{8}+\frac{1}{0.01}-{({3}^{3})}^{\frac{2}{3}}\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[\frac{1}{8}+\frac{1}{0.01}-{3}^{\frac{3\times 2}{3}}\]
Simplify  \(3\times 2\)  to  \(6\).
\[\frac{1}{8}+\frac{1}{0.01}-{3}^{\frac{6}{3}}\]
Simplify  \(\frac{6}{3}\)  to  \(2\).
\[\frac{1}{8}+\frac{1}{0.01}-{3}^{2}\]
Simplify  \({3}^{2}\)  to  \(9\).
\[\frac{1}{8}+\frac{1}{0.01}-9\]
Simplify  \(\frac{1}{0.01}\)  to  \(100\).
\[\frac{1}{8}+100-9\]
Simplify.
\[\frac{729}{8}\]

Decimal Form: 91.125