How to solve (3)^(2)+7(3)+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3)^(2)+7(3)+10 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$${ 3 }^{ 2 } +7(3)+10$$

Evaluate

$40$

Solution Steps

Calculate $3$ to the power of $2$ and get $9$.

$$9+7\times 3+10$$

Multiply $7$ and $3$ to get $21$.

$$9+21+10$$

Add $9$ and $21$ to get $30$.

$$30+10$$

Add $30$ and $10$ to get $40$.

$$40$$

Show Solution

Factor

$2^{3}\times 5$

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