$x=\frac{i\pi n_{1}}{\ln(3)}+\frac{3}{2}\text{, }n_{1}\in \mathrm{Z}$
$x=\frac{i\pi n_{2}}{\ln(3)}+\frac{5}{2}\text{, }n_{2}\in \mathrm{Z}$

$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$
$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$