$${ 3 }^{ N+1 } { 3 }^{ N+2 } =x \times { 3 }^{ N }$$
$x=27\times 3^{N}$
$N=\log_{3}\left(x\right)+\frac{2\pi n_{1}i}{\ln(3)}-3$
$n_{1}\in \mathrm{Z}$
$x\neq 0$
$N=\log_{3}\left(x\right)-3$
$x>0$
