How to solve (4)^(2)-5(4)-6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (4)^(2)-5(4)-6 | Equatix

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3(r+2s)=2t-4

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Question

$${ 4 }^{ 2 } -5(4)-6$$

Evaluate

$-10$

Solution Steps

Calculate $4$ to the power of $2$ and get $16$.

$$16-5\times 4-6$$

Multiply $5$ and $4$ to get $20$.

$$16-20-6$$

Subtract $20$ from $16$ to get $-4$.

$$-4-6$$

Subtract $6$ from $-4$ to get $-10$.

$$-10$$

Show Solution

Factor

$-10$

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