How to solve (4)^(2)+7(4)+10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (4)^(2)+7(4)+10 | Equatix

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3(r+2s)=2t-4

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Question

$${ 4 }^{ 2 } +7(4)+10$$

Evaluate

$54$

Solution Steps

Calculate $4$ to the power of $2$ and get $16$.

$$16+7\times 4+10$$

Multiply $7$ and $4$ to get $28$.

$$16+28+10$$

Add $16$ and $28$ to get $44$.

$$44+10$$

Add $44$ and $10$ to get $54$.

$$54$$

Show Solution

Factor

$2\times 3^{3}$

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