Question

$${ 4 }^{ 2 } + { 5 }^{ 2 } + { \left( \right) }^{ 2 } =21$$

Answer

[No Solution]

Solution


Remove parentheses.
\[{4}^{2}+{5}^{2}+{}^{2}=21\]
Simplify  \({4}^{2}\)  to  \(16\).
\[16+{5}^{2}+{}^{2}=21\]
Simplify  \({5}^{2}\)  to  \(25\).
\[16+25+{}^{2}=21\]
Simplify  \(16+25\)  to  \(41\).
\[41+{}^{2}=21\]
Since \(41+{}^{2}=21\) is false, there is no solution.
No Solution