$${ 4 }^{ \frac{ 3 }{ 2 } } + { 8 }^{ { \left( \frac{ 2 }{ 3 } \right) }^{ } } + \sqrt[ 3 ]{ -27 }$$
$9$
$$8+8^{\left(\frac{2}{3}\right)^{1}}+\sqrt[3]{-27}$$
$$8+8^{\frac{2}{3}}+\sqrt[3]{-27}$$
$$8+4+\sqrt[3]{-27}$$
$$12+\sqrt[3]{-27}$$
$$12-3$$
$$9$$
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$3^{2}$
