$${ 5 }^{ 2 } (x3)+9-5$$
$25x_{3}+4$
$$25x_{3}+9-5$$
$$25x_{3}+4$$
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$25$
$$\frac{\mathrm{d}}{\mathrm{d}x_{3}}(25x_{3}+9-5)$$
$$\frac{\mathrm{d}}{\mathrm{d}x_{3}}(25x_{3}+4)$$
$$25x_{3}^{1-1}$$
$$25x_{3}^{0}$$
$$25\times 1$$
$$25$$