$${ 6 }^{ 2 } -4 \times 1 \times -( { a }^{ 2 } +2a-8)$$
$4\left(a+1\right)^{2}$
$$36-4\times 1\left(-\left(a^{2}+2a-8\right)\right)$$
$$36-4\left(-\left(a^{2}+2a-8\right)\right)$$
$$36-4\left(-a^{2}-2a+8\right)$$
$$36+4a^{2}+8a-32$$
$$4+4a^{2}+8a$$
Show Solution
Hide Solution
$4a^{2}+8a+4$
