Question

$${ 6 }^{ 2 } +9x \frac { } { }$$

Answer

9*(4+x)

Solution


Simplify  \({6}^{2}\)  to  \(36\).
\[(36+9x)/\]
Regroup terms.
\[\frac{1}{(36+9x)}\]
Factor out the common term \(9\).
\[\frac{1}{\times 9}(4+x)\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[1\times 9(4+x)\]
Simplify.
\[9(4+x)\]