$$\{ 6 x y \} 13 x = 2 \}$$
$y=\frac{1}{39x^{2}}$
$x\neq 0$
$x=-\frac{\sqrt{39}y^{-\frac{1}{2}}}{39}$
$x=\frac{\sqrt{39}y^{-\frac{1}{2}}}{39}\text{, }y\neq 0$
$x=\frac{\sqrt{\frac{39}{y}}}{39}$
$x=-\frac{\sqrt{\frac{39}{y}}}{39}\text{, }y>0$
