$${ 9 }^{ 2 } +8+ { 6 }^{ 2 } +3- { 2 }^{ 3 } \div 2=$$
$124$
$$9^{2}+8+6^{2}+3-2^{2}$$
$$81+8+6^{2}+3-2^{2}$$
$$89+6^{2}+3-2^{2}$$
$$89+36+3-2^{2}$$
$$125+3-2^{2}$$
$$128-2^{2}$$
$$128-4$$
$$124$$
Show Solution
Hide Solution
$2^{2}\times 31$
