$${ a }^{ 2 } - \frac{ 4 }{ 3 } a+ \frac{ 4 }{ 9 }$$
$\frac{\left(3a-2\right)^{2}}{9}$
$$\frac{9a^{2}-12a+4}{9}$$
$$\left(3a-2\right)^{2}$$
$$\frac{\left(3a-2\right)^{2}}{9}$$
Show Solution
Hide Solution