Question

$${ a }^{ 2 } +2a-3a,entre,a+3$$

Answer

$$a^2-a,e^2*n*t*r,a+3$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{a}^{2}+2a-3a,{e}^{2}ntr,a+3\]
Collect like terms.
\[({a}^{2}+(2a-3a)),{e}^{2}ntr,a+3\]
Simplify  \({a}^{2}+(2a-3a)\)  to  \({a}^{2}-a\).
\[{a}^{2}-a,{e}^{2}ntr,a+3\]