Question

$${}_{4}^{\int6}x^{2}\cdot dx$$

Answer

$$6*4^int*x^3*d$$

Solution


Regroup terms.
\[6{x}^{2}xd\times {4}^{int}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[6{x}^{2+1}d\times {4}^{int}\]
Simplify  \(2+1\)  to  \(3\).
\[6{x}^{3}d\times {4}^{int}\]
Regroup terms.
\[6\times {4}^{int}{x}^{3}d\]