Solve \{9/16 * 4/12\} + \{9/16 * (- 3/9)\}

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Question

$$\{\frac{9}{16}\times\frac{4}{12}\}+\{\frac{9}{16}\times\frac{-3}{9}\}$$

Evaluate

$0$

Solution Steps

Reduce the fraction $\frac{4}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{9}{16}\times \frac{1}{3}+\frac{9}{16}\times \frac{-3}{9}$$

Multiply $\frac{9}{16}$ times $\frac{1}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 1}{16\times 3}+\frac{9}{16}\times \frac{-3}{9}$$

Do the multiplications in the fraction $\frac{9\times 1}{16\times 3}$.

$$\frac{9}{48}+\frac{9}{16}\times \frac{-3}{9}$$

Reduce the fraction $\frac{9}{48}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{16}+\frac{9}{16}\times \frac{-3}{9}$$

Reduce the fraction $\frac{-3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{16}+\frac{9}{16}\left(-\frac{1}{3}\right)$$

Multiply $\frac{9}{16}$ times $-\frac{1}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{16}+\frac{9\left(-1\right)}{16\times 3}$$

Do the multiplications in the fraction $\frac{9\left(-1\right)}{16\times 3}$.

$$\frac{3}{16}+\frac{-9}{48}$$

Reduce the fraction $\frac{-9}{48}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{16}-\frac{3}{16}$$

Subtract $\frac{3}{16}$ from $\frac{3}{16}$ to get $0$.

$$0$$

Show Solution

Factor

$0$