How to solve (2-sqrt(3))^(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2-sqrt(3))^(2) | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$${ \left(2- \sqrt{ 3 } \right) }^{ 2 }$$

Evaluate

$7-4\sqrt{3}\approx 0.07179677$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(2-\sqrt{3}\right)^{2}$.

$$4-4\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

The square of $\sqrt{3}$ is $3$.

$$4-4\sqrt{3}+3$$

Add $4$ and $3$ to get $7$.

$$7-4\sqrt{3}$$

Show Solution

Expand

$7-4\sqrt{3}$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(2-\sqrt{3}\right)^{2}$.

$$4-4\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

The square of $\sqrt{3}$ is $3$.

$$4-4\sqrt{3}+3$$

Add $4$ and $3$ to get $7$.

$$7-4\sqrt{3}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Expand

Solution Steps