$${ \left(3 { x }^{ -1 } y \right) }^{ 2 } \times \frac{ x { z }^{ 4 } }{ { z }^{ 3 } }$$
$\frac{9zy^{2}}{x}$
$$3^{2}\left(x^{-1}\right)^{2}y^{2}\times \frac{xz^{4}}{z^{3}}$$
$$3^{2}x^{-2}y^{2}\times \frac{xz^{4}}{z^{3}}$$
$$9x^{-2}y^{2}\times \frac{xz^{4}}{z^{3}}$$
$$9x^{-2}y^{2}xz$$
$$9x^{-1}y^{2}z$$
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