$${ \left(3 \frac{ 3 }{ 6 } \right) }^{ 2 } +6$$
$\frac{73}{4}=18.25$
$$\left(\frac{18+3}{6}\right)^{2}+6$$
$$\left(\frac{21}{6}\right)^{2}+6$$
$$\left(\frac{7}{2}\right)^{2}+6$$
$$\frac{49}{4}+6$$
$$\frac{73}{4}$$
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$\frac{73}{2 ^ {2}} = 18\frac{1}{4} = 18.25$
