Question

$${ \left(4x \right) }^{ 2 } + { 1 }^{ 2 } =16 { x }^{ 2 }$$

Answer

[No Solution]

Solution


Use Multiplication Distributive Property: \({(xy)}^{a}={x}^{a}{y}^{a}\).
\[{4}^{2}{x}^{2}+{1}^{2}=16{x}^{2}\]
Simplify  \({4}^{2}\)  to  \(16\).
\[16{x}^{2}+{1}^{2}=16{x}^{2}\]
Simplify  \({1}^{2}\)  to  \(1\).
\[16{x}^{2}+1=16{x}^{2}\]
Cancel \(16{x}^{2}\) on both sides.
\[1=0\]
Since \(1=0\) is false, there is no solution.
No Solution