$${ \left( { 8 }^{ 2 } \right) }^{ 2-9 } (6+3)$$
$\frac{9}{4398046511104}=2.046363079 \cdot 10^{-12}$
$$64^{2-9}\left(6+3\right)$$
$$64^{-7}\left(6+3\right)$$
$$\frac{1}{4398046511104}\left(6+3\right)$$
$$\frac{1}{4398046511104}\times 9$$
$$\frac{9}{4398046511104}$$
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$\frac{3 ^ {2}}{2 ^ {42}} = 2.0463630789890885 \times 10^{-12}$
