Question

$${ \left( \frac{ 2 }{ 3 } { \times }^{ 2 } -1 \right) }^{ 2 }$$

Answer

$$((2*^3)/3-1)^2$$

Solution


Remove parentheses.
\[{(\frac{2}{3}{}^{2}-1)}^{2}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[{(\frac{2{}^{2}}{3}-1)}^{2}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{(\frac{2{}^{3}}{3}-1)}^{2}\]