Question

$${ \left( \frac{ 4 }{ 5 } \right) }^{ 6 } { \times }^{ { \left( \frac{ 3 }{ 2 } \right) }^{ 6 } }$$

Answer

$$(4096*^(793/64))/15625$$

Solution


Use Division Distributive Property: \({(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}\).
\[\frac{{4}^{6}}{{5}^{6}}{}^{{(\frac{3}{2})}^{6}}\]
Simplify  \({4}^{6}\)  to  \(4096\).
\[\frac{4096}{{5}^{6}}{}^{{(\frac{3}{2})}^{6}}\]
Simplify  \({5}^{6}\)  to  \(15625\).
\[\frac{4096}{15625}{}^{{(\frac{3}{2})}^{6}}\]
Use Division Distributive Property: \({(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}\).
\[\frac{4096}{15625}{}^{\frac{{3}^{6}}{{2}^{6}}}\]
Simplify  \({3}^{6}\)  to  \(729\).
\[\frac{4096}{15625}{}^{\frac{729}{{2}^{6}}}\]
Simplify  \({2}^{6}\)  to  \(64\).
\[\frac{4096}{15625}{}^{\frac{729}{64}}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{4096{}^{\frac{729}{64}}}{15625}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{4096{}^{\frac{793}{64}}}{15625}\]