Question

$${ \left( \frac{ { 80 }^{ x } + { 16 }^{ x } }{ { 20 }^{ x } + { 4 }^{ x } } \right) }^{ (2 { \left(x) \right) }^{ -1 } }$$

Answer

$$(80^x+16^x)^(1/(2*x))/(20^x+4^x)^(1/(2*x))$$

Solution


Use Division Distributive Property: \({(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}\).
\[\frac{{({80}^{x}+{16}^{x})}^{{(2x)}^{-1}}}{{({20}^{x}+{4}^{x})}^{{(2x)}^{-1}}}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{\sqrt[2x]{{80}^{x}+{16}^{x}}}{\sqrt[2x]{{20}^{x}+{4}^{x}}}\]