Question

$${ \left( \sin x+ \cos x \right) }^{ 2 } -1=2 \sin x \times \cos x$$

Answer

[Infinite Solutions]

Solution


Expand.
\[2\sin{x}\cos{x}+1-1=2\sin{x}\cos{x}\]
Simplify  \(2\sin{x}\cos{x}+1-1\)  to  \(2\sin{x}\cos{x}\).
\[2\sin{x}\cos{x}=2\sin{x}\cos{x}\]
Since both sides equal, there are infinitely many solutions.
Infinitely Many Solutions