Add \(9\) to both sides.
\[{(x-3)}^{2}=9\]
Take the square root of both sides.
\[x-3=\pm \sqrt{9}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[x-3=\pm 3\]
Break down the problem into these 2 equations.
\[x-3=3\]
\[x-3=-3\]
Solve the 1st equation: \(x-3=3\).
Add \(3\) to both sides.
\[x=3+3\]
Simplify \(3+3\) to \(6\).
\[x=6\]
\[x=6\]
Solve the 2nd equation: \(x-3=-3\).
Cancel \(-3\) on both sides.
\[x=0\]
\[x=0\]
Collect all solutions.
\[x=6,0\]
x=6,0
