$${ \left(x-7 \right) }^{ 2 } + { \left(y+3 \right) }^{ 2 } = { \left(3 \sqrt{ 2 } \right) }^{ 2 }$$
$x=-\sqrt{9-6y-y^{2}}+7$
$x=\sqrt{9-6y-y^{2}}+7$
$y=-\left(\sqrt{-x^{2}+14x-31}+3\right)$
$y=\sqrt{-x^{2}+14x-31}-3$
$x=-\sqrt{9-6y-y^{2}}+7$
$x=\sqrt{9-6y-y^{2}}+7\text{, }y\geq -3\sqrt{2}-3\text{ and }y\leq 3\sqrt{2}-3$
$y=-\left(\sqrt{-x^{2}+14x-31}+3\right)$
$y=\sqrt{-x^{2}+14x-31}-3\text{, }x\geq 7-3\sqrt{2}\text{ and }x\leq 3\sqrt{2}+7$
