Question

$${ \left(x- \frac{ 2 }{ 7 } \right) }^{ 2 } - \frac{ 4 }{ 49 } =0$$

Answer

x=4/7,0

Solution


Add \(\frac{4}{49}\) to both sides.
\[{(x-\frac{2}{7})}^{2}=\frac{4}{49}\]
Take the square root of both sides.
\[x-\frac{2}{7}=\pm \sqrt{\frac{4}{49}}\]
Simplify  \(\sqrt{\frac{4}{49}}\)  to  \(\frac{\sqrt{4}}{\sqrt{49}}\).
\[x-\frac{2}{7}=\pm \frac{\sqrt{4}}{\sqrt{49}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[x-\frac{2}{7}=\pm \frac{2}{\sqrt{49}}\]
Since \(7\times 7=49\), the square root of \(49\) is \(7\).
\[x-\frac{2}{7}=\pm \frac{2}{7}\]
Break down the problem into these 2 equations.
\[x-\frac{2}{7}=\frac{2}{7}\]
\[x-\frac{2}{7}=-\frac{2}{7}\]
Solve the 1st equation: \(x-\frac{2}{7}=\frac{2}{7}\).
\[x=\frac{4}{7}\]
Solve the 2nd equation: \(x-\frac{2}{7}=-\frac{2}{7}\).
\[x=0\]
Collect all solutions.
\[x=\frac{4}{7},0\]

Decimal Form: 0.571429, 0