Solve (y-4)^(2)-(y+2)\times8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$${ \left(y-4 \right) }^{ 2 } -(y+2) \times 8$$

Evaluate

$y\left(y-16\right)$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(y-4\right)^{2}$.

$$y^{2}-8y+16-\left(y+2\right)\times 8$$

Use the distributive property to multiply $y+2$ by $8$.

$$y^{2}-8y+16-\left(8y+16\right)$$

To find the opposite of $8y+16$, find the opposite of each term.

$$y^{2}-8y+16-8y-16$$

Combine $-8y$ and $-8y$ to get $-16y$.

$$y^{2}-16y+16-16$$

Subtract $16$ from $16$ to get $0$.

$$y^{2}-16y$$

Expand

$y^{2}-16y$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(y-4\right)^{2}$.

$$y^{2}-8y+16-\left(y+2\right)\times 8$$

Use the distributive property to multiply $y+2$ by $8$.

$$y^{2}-8y+16-\left(8y+16\right)$$

To find the opposite of $8y+16$, find the opposite of each term.

$$y^{2}-8y+16-8y-16$$

Combine $-8y$ and $-8y$ to get $-16y$.

$$y^{2}-16y+16-16$$

Subtract $16$ from $16$ to get $0$.

$$y^{2}-16y$$